the sum of infinite of gp whose first is 28 and fourth term is 4by49

Asked by surain bhandari | 9th Aug, 2010, 04:25: PM

Expert Answer:

Dear Student
Following is the solution of your question
Let the GP be a,ar,ar2,ar3,ar4,.......  
Given a =28
ar3 =4/49
So r = 1/7
 
Now sum of infinite GP is
a/(1-r)=28/(1-1/7)=196/6
Regards
Team Topper

Answered by  | 9th Aug, 2010, 06:29: PM

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