The speed of a moving body is halved.What change takes place in its kinetic energy?

Asked by narinder | 14th Sep, 2008, 01:01: PM

Expert Answer:

The K.E. reduces by 4 times.

K.E. = 1mv2/2

Answered by  | 15th Sep, 2008, 01:11: AM

Queries asked on Sunday & after 7pm from Monday to Saturday will be answered after 12pm the next working day.