CBSE Class 12-science Answered
The Solution set of the given equation -
Asked by thebluebloo | 07 Apr, 2009, 06:59: PM
Expert Answer
logx2log2x2=log4x2
logx2log2x2=log4x2
⇒ (log2/ logx) Χ (log2/log2x) = (log2/log4x)
⇒ log 2. log4x = logx. log2x
⇒ log2 (log4 + logx) = logx (log2 + logx)
⇒ log2. log4 = (log x)2
⇒ 2 (log2)2 = (log x)2
⇒ log x = ± 
2 . log2
⇒ x = e±2log2
⇒ x = 22 and 2-2
Hence the correct option is (1)
Answered by | 20 May, 2009, 03:44: PM
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