the solution of the system of linear equations 
31x+43y=117, 43x+31y=105 is

Asked by Sanmit Ratnaparkhi | 9th Jul, 2014, 08:52: PM

Expert Answer:

G i v e n space s y s t e m space o f space e q u a t i o n s space i s : 31 x plus 43 y equals 117... left parenthesis 1 right parenthesis 43 x plus 31 y equals 105... left parenthesis 2 right parenthesis S u b t r a c t i n g space e q u a t i o n space left parenthesis 2 right parenthesis space f r o m space left parenthesis 1 right parenthesis comma space w e space h a v e minus 12 x plus 12 y equals 12 rightwards double arrow minus x plus y equals 1 A d d i n g space e q u a t i o n s space left parenthesis 1 right parenthesis space a n d space left parenthesis 2 right parenthesis space w e space h a v e comma 74 x plus 74 y equals 222 rightwards double arrow x plus y equals 3 N o w space l e t space u s space s o l v e space t h e space s y s t e m space o f space f o l l o w i n g space e q u a t i o n s : minus x plus y equals 1.... left parenthesis 3 right parenthesis x plus y equals 3.... left parenthesis 4 right parenthesis A d d i n g space e q u a t i o n s space left parenthesis 3 right parenthesis space a n d space left parenthesis 4 right parenthesis comma space w e space h a v e comma 2 y equals 4 rightwards double arrow y equals 2 S u b s t i t u t i n g space t h e space v a l u e space o f space y space i n space e q u a t i o n space left parenthesis 3 right parenthesis comma space w e space h a v e minus x plus 2 equals 1 rightwards double arrow x equals 1 T h u s space t h e space s o l u t i o n space o f space t h e space g i v e n space s y s t e m space o f space e q u a t i o n s space i s space open parentheses 1 comma 2 close parentheses

Answered by Vimala Ramamurthy | 10th Jul, 2014, 10:05: AM

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