CBSE Class 6 Answered
The smallest number which when diminished by 7, is divisible 12, 16, 18, 21 and 28 is:
Asked by Topperlearning User | 13 May, 2014, 03:19: PM
Expert Answer
L.C.M. of 12,16, 18, 21, 28:
Factors of 12 - 2 x 2 x 3
Factors of 16 - 2 x 2 x 2 x 2
Factors of 18 - 2 x 3 x 3
Factors of 21 - 3 x 7
Factors of 28 - 2 x 2 x 7
LCM - 2 x 2 x 2 x 2 x 3 x 3 x 7 = 1008
Required number = (L.C.M. of 12,16, 18, 21, 28) + 7
= 1008 + 7
= 1015
Answered by | 13 May, 2014, 05:19: PM
Concept Videos
CBSE 6 - Maths
Asked by dr.niveditasahoo | 21 Sep, 2023, 12:18: PM
ANSWERED BY EXPERTCBSE 6 - Maths
Asked by allagaddasreereddy | 14 Aug, 2022, 11:32: PM
ANSWERED BY EXPERTCBSE 6 - Maths
Asked by bijan1971 | 30 Sep, 2021, 08:06: AM
ANSWERED BY EXPERTCBSE 6 - Maths
Asked by truptigavit66.6dgatl | 28 Sep, 2021, 06:03: PM
ANSWERED BY EXPERTCBSE 6 - Maths
Asked by kashti2610 | 08 Aug, 2021, 12:49: PM
ANSWERED BY EXPERTCBSE 6 - Maths
Asked by sushilasushila35756 | 01 Aug, 2021, 07:43: PM
ANSWERED BY EXPERTCBSE 6 - Maths
Asked by s1081divyanshi10860 | 24 Jun, 2021, 09:18: AM
ANSWERED BY EXPERTCBSE 6 - Maths
Asked by aryan975404 | 26 Sep, 2020, 05:25: PM
ANSWERED BY EXPERTCBSE 6 - Maths
Asked by aarjunain54321 | 04 Sep, 2020, 08:54: PM
ANSWERED BY EXPERT
