The sides of an equilateral triangular field are 51 m, 37 m and 20 m.Find the area of no. of rose beds that can be prepared in the field, if each rose bed on an average occupies 6 sq. m of space ?

Asked by nisha_vini29 | 18th May, 2017, 10:52: PM

Expert Answer:

begin mathsize 14px style SIdes space of space triangular space field space are space 51 space cm comma space 37 space cm space and space 20 space cm
rightwards double arrow straight s equals fraction numerator 51 plus 37 plus 20 over denominator 2 end fraction equals 108 over 2 equals 54 space straight m
Area space of space triangular space field
equals square root of 54 left parenthesis 54 minus 51 right parenthesis left parenthesis 54 minus 37 right parenthesis left parenthesis 54 minus 20 right parenthesis end root
equals square root of 54 cross times 3 cross times 17 cross times 34 end root
equals 306 space straight m squared
Area space of space each space rose space bed equals 6 space straight m squared
rightwards double arrow Number space of space rose space beds space equals 306 over 6 equals 51 end style

Answered by Rashmi Khot | 19th May, 2017, 09:21: AM