The side AC of a triangle ABC is produced to E such that CE = 1/2 AC. If D is midpoint of BC and ED produced meets AB in F, and CP, DQ are drawn parallel to BA. Prove that FD = 1/3 EF
Asked by Paresh | 8th Dec, 2015, 04:26: PM
Answered by Vijaykumar Wani | 9th Dec, 2015, 11:32: AM
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