the side AB of a parallelogram ABCD is produced to any point P. a line through A and parallel to CP meets CB produced at Q and then the parallelogram PBQR is completed. show that ar(//gm ABCD)=ar(//gm PBQR)
Asked by shweta mondal
| 12th Jan, 2014,
09:32: AM
Expert Answer:
Answered by
| 12th Jan, 2014,
10:09: PM
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