the side AB of a parallelogram ABCD is produced to any point P. a line through A and parallel to CP meets CB produced at Q and then the parallelogram PBQR is completed. show that ar(//gm ABCD)=ar(//gm PBQR)

Asked by shweta mondal | 12th Jan, 2014, 09:32: AM

Expert Answer:

Answered by  | 12th Jan, 2014, 10:09: PM

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