The riddle of spirit...

Asked by  | 6th Feb, 2010, 08:07: PM

Expert Answer:

Let the spirit be a % and b % in vessels A and B respectively.

3 parts from A and 2 parts from B, total parts, 5.

Amount of spirit in 3 parts of A = (a/100)3.

Amount of spirit in 2 parts of B = (b/100)2.

Amount of spirit in 5 parts, = (0.29)5.

These amount must tally.

(Amount of spirit in 3 parts of A)+(Amount of spirit in 2 parts of B) = Amount of spirit in 5 parts

(a/100)3 + (b/100)2 = (0.29)5

3a + 2b = 145 ..........(1)

Similary for second part we get,

a + 9b = 340 ..........(2)

Solving (1) and (2), we find,

a = 25, b = 35,

Percentage of spirit in A = 25

Percentage of spirit in B = 35

Regards,

Team,

TopperLearning.

 

Answered by  | 6th Feb, 2010, 09:12: PM

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