The relation b/w time t and distance x is t = ax.sq + bx . where a & b are constants . the retardation is given by : a) 2a(v).cube b) 2b(v).cube c) 2ab(v).cube d 2(bv).cube Please explain ??

Asked by shuchi.saumya | 5th Sep, 2010, 12:00: AM

Expert Answer:

Option 1 is true. You must just differentiate the given equation t = ax.sq + bx twice, with respect to t and then substitute the value of 2ax+b as equal to 1/v (this can be get from the first diffentiation of the given equation)

Answered by  | 6th Sep, 2010, 11:41: PM

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