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CBSE Class 12-science Answered

The reaction: 2NO ---> 2NO + O 2  has an activation energy of 110 kJmol-1. At 4000C, the rate constant is 7.8mol-1Ls-1. What is the value of the rate constant at 4300C? please give the answer with proper calculation of log 
Asked by modi72879 | 08 Mar, 2018, 10:04: AM
answered-by-expert Expert Answer
Given colon straight E subscript straight a space equals space 110 space kJmol to the power of negative 1 end exponent straight T subscript 1 space equals space 400 to the power of ring operator straight C straight T subscript 1 space equals space 673 space straight K straight k subscript 1 space equals space 7.8 space mol to the power of negative 1 end exponent LSec to the power of negative 1 end exponent straight T subscript 2 space equals space 430 to the power of ring operator straight C straight T subscript 2 space equals space 703 space straight K straight k subscript 2 space equals space ? We space have comma log straight k subscript 2 over straight k subscript 1 space equals fraction numerator straight E subscript straight a over denominator 2.303 cross times straight R end fraction open square brackets 1 over straight T subscript 1 minus 1 over straight T subscript 2 close square brackets log fraction numerator straight k subscript 2 over denominator 7.8 end fraction space equals fraction numerator 110 cross times 1000 over denominator 2.303 cross times 8.314 end fraction open square brackets 1 over 673 minus 1 over 703 close square brackets logk subscript 2 minus left parenthesis space log space 7.8 right parenthesis space equals space 5744.98 open square brackets fraction numerator 703 minus 673 over denominator 673 cross times 704 end fraction close square brackets logk subscript 2 space minus 0.8920 space equals space 5867.78 cross times left parenthesis 6.54 cross times 10 to the power of negative 5 end exponent right parenthesis space space space space space space space space space space space space space logk subscript 2 space space equals space 0.3839 plus 0.8920 space space space space space space space space space space space space space logk subscript 2 space end subscript space space equals space 1.2759 space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space straight k subscript 2 space space equals antilog left parenthesis 1.2759 right parenthesis space space space space space space space space space space space space space space straight k subscript 2 equals space 18 space mol to the power of negative 1 end exponent LSec to the power of negative 1 end exponent
Answered by Varsha | 08 Mar, 2018, 11:01: AM

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