CBSE Class 11-science Answered
The ratio of sums of n-terms of two arithematic progressions is (3n-13):(5n+21). The ratio of 24th term of the two series is?
Asked by Manan Kinjawadekar | 15 Apr, 2013, 07:14: PM
Expert Answer
let first term and common difference of first AP be A & D and for the second AP be "a" & "d"
therefor (3n-13)/(5n+21)=(n/2(2A+(n-1)D))/(n/2(2a+(n-1)d))
therefor (3n-13):(5n+21)=(2A+(n-1)D))/(2a+(n-1)d)
now putting n=47 on both sides
(3*47-13)/(5*47+21)=(A+23D)/(a+23d)
therfor ratio of there 24 th term=1/2
Answered by | 15 Apr, 2013, 08:08: PM
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