the radius of earth is reduced by 4%. the mass of earth remains unchanged. what will be the change in escape velocity???
Asked by toppin | 4th Nov, 2010, 06:24: PM
The acceleration due to gravity at the surface of earth is g = G m / R2 .
The radius of eath decreases by 4 %, therefore
R' = R - 0.04 R = 0.96R.
Now acceleration due to gravity will be :
g' = GM / ( 0.96 R )2 = 1.09 g
Percentage increase in acceleration due to gravity
[(g' - g )/g ] x 100 = 9 %
We hope this clarifies your doubt.
Answered by | 6th Nov, 2010, 03:50: PM
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