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CBSE Class 11-science Answered

The question is attached above. Please send step by step complete solution. I also request you please do not send any web link to this question because I am unable to  open the link every time  .
Asked by sudhanshubhushanroy | 14 Dec, 2017, 06:55: AM
answered-by-expert Expert Answer
begin mathsize 16px style straight D right parenthesis cos left parenthesis straight A minus straight B right parenthesis equals 31 over 32 cos left parenthesis straight A minus straight B right parenthesis equals fraction numerator 1 minus tan squared open parentheses begin display style fraction numerator straight A minus straight B over denominator 2 end fraction end style close parentheses over denominator 1 plus tan squared open parentheses fraction numerator straight A minus straight B over denominator 2 end fraction close parentheses end fraction rightwards double arrow tan open parentheses fraction numerator straight A minus straight B over denominator 2 end fraction close parentheses equals fraction numerator 1 over denominator square root of 63 end fraction tan open parentheses fraction numerator straight A minus straight B over denominator 2 end fraction close parentheses equals fraction numerator straight a minus straight b over denominator straight a plus straight b end fraction cot straight C over 2 fraction numerator straight a minus straight b over denominator straight a plus straight b end fraction cot straight C over 2 equals fraction numerator 1 over denominator square root of 63 end fraction rightwards double arrow tan straight C over 2 equals fraction numerator square root of 63 over denominator 9 end fraction cosC equals fraction numerator 1 minus tan squared open parentheses begin display style straight C over 2 end style close parentheses over denominator 1 plus tan squared open parentheses straight C over 2 close parentheses end fraction equals 1 over 8 Using space straight c squared equals straight a squared plus straight b squared minus 2 abcosC find space straight c space you space will space get space straight c equals 6. straight C right parenthesis Using space Let space straight R space be space the space centre space of space circumcentre space and space straight r space be space the space incentre. RcosA equals straight r using space half space angle space formulae space you space get space cosB plus cosC equals 1 straight A right parenthesis left parenthesis straight a plus straight b plus straight c right parenthesis left parenthesis straight b plus straight c minus straight a right parenthesis equals λbc Solving space this space we space get fraction numerator straight b squared plus straight c squared minus straight a squared over denominator 2 bc end fraction equals straight lambda over 2 minus 1 cosA equals straight lambda over 2 minus 1 minus 1 less than cosA less than 1 rightwards double arrow 0 less than straight lambda less than 4 Hence comma space straight lambda equals 3 space end style
Answered by Sneha shidid | 18 Dec, 2017, 05:15: PM

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