The power of the wre having potential difference 200 V across its end is 100 W.If the wire is cut into two equal parts,then what will be the energy per sec consumed by the wire.
Asked by kharendra | 10th Jul, 2015, 11:28: PM
The initial power of the wire is 100 W.
Now, when the wire is cut into two equal parts, its resistance as well as voltage drop both are equal and reduced to half the original values.
That is R1 = R2 = R/2
V1 = V2 = V/2
So, we get P1 = P2 = P/2
Hence, if we calculate the combined power, it will be P = P1 + P2 = 100 W
Hence, the energy consumed per second is E = P/t = 100/1 = 100 J
Answered by Romal Bhansali | 12th Jul, 2015, 12:21: PM
- the instrument based on null deflection method is
- 1 kilo watt = ?
- WHY CURRENT OF 220V IS HARMFUL ?
- Why can we not use rubber to make electric wires?
- Why do we prefer a potentiometer of longer length for getting the accurate readings?
- What do you mean by sensitivity of potentiometer? How can we increase the sensitivity of potentiometer?
- A potentiometer wire is 5 m long and a potential difference of 6 V is maintained between its ends. Find the emf of a cell which balances against a length of 180 cm of the potentiometer wire.
- The potential gradient along the length of uniform wire is 20 Vm-1. The length of wire is 1m. What is the potential difference across two points on the wire separated by distance 40 cm?
- State the uses of potentiometer
- The force on an electron in a potentiometer wire is 3.2 X 10-19 N. The length of the wire is 6 m. What is the e.m.f of the battery connected across the wire?
Kindly Sign up for a personalised experience
- Ask Study Doubts
- Sample Papers
- Past Year Papers
- Textbook Solutions
Verify mobile number
Enter the OTP sent to your number