The position (x) of a particle at time t, is given by the relation, x(t)=v0/a(1-e-at), where v0 is a constant and a>0. The dimensions of v0 and a are respectively  

Asked by Anil | 17th May, 2017, 09:21: PM

Expert Answer:

begin mathsize 12px style The space position space of space the space particle space at space straight a space time space straight t space is space given space as
straight x left parenthesis straight t right parenthesis equals fraction numerator straight v subscript straight o over denominator straight a left parenthesis 1 minus straight e to the power of negative at end exponent right parenthesis end fraction
As space straight x space denotes space position comma space left square bracket straight x right square bracket space equals space straight m comma space straight i. straight e. space distance space in space metre.
Here space the space exponential comma space straight e to the power of at space must space be space dimensionless.
Hence space left square bracket straight a right square bracket equals straight s to the power of negative 1 end exponent space or space inverse space time.
or space straight a space equals space left square bracket straight M to the power of 0 space straight L to the power of 0 space straight T to the power of negative 1 end exponent space right square bracket
rightwards arrow fraction numerator open square brackets straight V subscript straight o close square brackets over denominator open square brackets straight a close square brackets end fraction space equals space open square brackets straight V subscript straight o close square brackets space straight s space equals space straight m
Hence space straight V subscript 0 space has space dimensions space of space velocity comma space straight i. straight e. space left square bracket straight V subscript 0 right square bracket equals ms to the power of negative 1 end exponent
or space straight V subscript 0 space equals space left square bracket straight M to the power of 0 space straight L to the power of 1 space straight T to the power of negative 1 end exponent right square bracket
end style

Answered by Yashvanti Jain | 18th May, 2017, 02:25: PM