the position of the particle along x-axis varies with time as

x = 4t2 - 6t + 1, then:

(a) What is the velocity at t = 0?

(b) When does velocity become zero?

 

Asked by Masood khan | 15th Jun, 2015, 01:07: PM

Expert Answer:

Given equation: x = 4t2 - 6t + 1
Differentiating the above eqution wrt time, we get:
 
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Answered by Yashvanti Jain | 15th Dec, 2017, 03:37: PM