The polynomials ax3+3*2-3 and 2*3-5x+a when divided by (x-4) leave the same remainder , find the value of 'a'.

Asked by  | 17th May, 2012, 11:48: AM

Expert Answer:

     Let       f(x) = ax3 + 3x2 – 3

      and      g(x) = 2x3 – 5x + a

      f(4) = a x 43 + 3 x 42 – 3

               = 64a + 48 – 3

               = 64a + 45

 

         g(4) = 2 x 43 – 5 x 4 + a

                = 128 – 20 + a

                = 108 + a

 

It is given that:

                    f(4) = g(4)

                 64a + 45 = 108 + a

                   64a – a = 108 – 45

                          63a = 63

                              a = 63/ 63 = 1

 The value of a is 1.

Answered by  | 17th May, 2012, 12:04: PM

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