The partial pressure of ethane over a saturated solution containing 6.56*10-2(-2 is in power of 10)gram of ethane is 1bar.If the solution contains 5*10-2(-2 is in power of 10)g of ethane , then what shall be partial pressure of the gas?

Asked by RAHUL | 28th May, 2013, 02:17: PM

Expert Answer:

According to Henry's law,
 
m= k x p
 
6.56 x 10-2 g = k x 1 bar
 
so, k = 6.56 x 10-2 g bar-1
 
Now, if new m = 5 x 10-2 g
 
then 5 x 10-2 g = 6.56 x 10-2 x p
 
Hence, p = 5 x 10-2/6.56 x 10-2
 
             = 0.76 bar

Answered by  | 29th May, 2013, 11:46: AM

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