the oxidation state of iodine in

Asked by Amyra B | 7th Jun, 2013, 10:29: PM

Expert Answer:

Oxidation state of I in H4IO-6   is  calculated in the following way:
4 *1 +x+ 6*(-2)=-1 ; x=7
where x= oxidation state of iodine 
1 is the oxidation state of hydrogen and -2 is the oxidation state of oxygen

Answered by  | 8th Jun, 2013, 11:55: AM

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