The neck and bottom of a bottle are 2cm and 20 cm in diameter respectively. The cork is pressed with same pressure. If the cork is pressed with a force of 1.2 kgf on the neck of the bottle, the force exerted on the bottom of the bottle will be:

Asked by victor Hemrom | 28th Nov, 2013, 08:56: PM

Expert Answer:

Given that,
 

Diameter of the neck is = 2 cm = 0.02 m

So, area of cross-section of the neck is,

a = ∏d 2 /4 = 0.000314 m 2

Diameter of the bottom is = 20 cm = 0.2 m

So, area of cross-section of the bottom is,

A = ∏d 2 /4 = 0.0314 m 2


Force applied to the cork, f = 1.2 kgf

Let F be the force at the bottom.

According to pascal's law,

F/A = f/a

=> F = (f/a)A = (1.2/0.000314)(0.0314) = 120 kgf

 

Answered by Komal Parmar | 29th Nov, 2013, 12:08: PM

Queries asked on Sunday & after 7pm from Monday to Saturday will be answered after 12pm the next working day.