The neck and bottom of a bottle are 2cm and 20 cm in diameter respectively. The cork is pressed with same pressure. If the cork is pressed with a force of 1.2 kgf on the neck of the bottle, the force exerted on the bottom of the bottle will be:

Given that,

 

Diameter of the neck is = 2 cm = 0.02 m

So, area of cross-section of the neck is,

a = ∏d ² /4 = 0.000314 m ²

Diameter of the bottom is = 20 cm = 0.2 m

So, area of cross-section of the bottom is,

A = ∏d ² /4 = 0.0314 m ²

Force applied to the cork, f = 1.2 kgf

Let F be the force at the bottom.

According to pascal's law,

F/A = f/a

=> F = (f/a)A = (1.2/0.000314)(0.0314) = 120 kgf