The mth term of a H.P. is n snd th nth term is m.Prove that pth term is mn/p?
Asked by | 6th Jul, 2008, 11:05: PM
let H.P. be 1/a , 1/(a+d) , 1/(a+2d),....
then given a+(m-1)d = 1/n
and a+(n-1)d = 1/m
solving for a and d we get a = 1/mn and d = -1/mn
then a+(p-1)d= 1/mn + (p-1)(-1/mn) = p/mn
so pth term of H.P. will be 1/(a+(p-1)d) = mn/p
Answered by | 12th Sep, 2008, 12:21: AM
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