the maximum kinetic energy of photoelectrons ejected from a metal when it is irradiated with a radiation of frequency 2 x 10^14 hertz is 6.63 x 10^-20. calculate the threshold energy.

Asked by  | 3rd May, 2013, 05:54: PM

Expert Answer:

hv = W + KE

6.6 x 10 ^-34  X 2 X10 ^ 14 = W + 6.63 x 10^ 20

          W = 6.57 x 10^20

Answered by  | 6th May, 2013, 10:32: AM

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