The mass of 350 cm3 of a diatomic gas at 273K at 2 atmospheres pressure is one gram. Calculate the mass of one atom of the gas.

Asked by  | 7th May, 2012, 12:04: AM

Expert Answer:

PV = nRT
2 x 350  = 1 /M X 82.1 X 273
M = 82.1 x 273 /700
 M=32
6.023 X 10 23 atoms has mass = 32 g
1 atom = 32 / 6.023 x1023 g
   = 5.3 X 10 -23g.

Answered by  | 8th May, 2012, 09:38: PM

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