The length of a potentiometer wire is 1200 cm and it carries a current of 80mA .FOR A CELL F EMF 4 V AND INTERNAL RESISTANCE 20 ohm the null point is found to be a 1000cm .If a voltmeter is connected across the cell the balancing length is decreased by 20 cm.Find i) resistance of the whole wire
ii) reading of the voltmeter
iii)resistance of voltmeter
Asked by Subhashree Lenka | 14th May, 2015, 07:38: PM
Given that the length of the potentiometer wire = 1200 cm
Current through the potentiometer wire, I = 80 mA = 80 × 10-3 A
1000 cm of potentiometer wire balances the cell of emf 4 V
Answered by Jyothi Nair | 15th May, 2015, 09:12: AM
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