The Ksp for AgCl is 1.8 x 1010. What is the molar solubility of AgCl in pure water?
Asked by Topperlearning User | 16th Jun, 2016, 05:25: PM
Let x be the molar solubility, then
AgCl Ag+ + Cl-
x = (1.8 x 1010)1/2
= 1.3 x 10-5 M
Answered by | 16th Jun, 2016, 07:25: PM
- pls explain
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