The Ksp for AgCl is 1.8 x 1010. What is the molar solubility of AgCl in pure water?

Asked by Topperlearning User | 16th Jun, 2016, 05:25: PM

Expert Answer:

Let x be the molar solubility, then
AgCl Error: the service is unavailable. Ag+ + Cl-
             x        x
 
x = (1.8 x 1010)1/2

   = 1.3 x 10-5 M

Answered by  | 16th Jun, 2016, 07:25: PM