The K.E. of a body increases by 300%. The momentum of the body would increase by what percentage?

Asked by akankshyasahu | 3rd May, 2012, 09:48: PM

Expert Answer:

E = (1/2)mv^2 = (1/2)m^2v^2/m
=> E = (1/2) P^2/m
300% increase in means E becomes 4E
=> P becomes 2P
=> increase in P = 2P - P = P
= 100% increase in P.

Answered by  | 4th May, 2012, 09:02: AM

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