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CBSE Class 12-science Answered

The incorrect order of decreasing oxidation number of S in compounds is: H2 S2 O7 > Na2 S4 O6 > Na2 S2 O3 > S8 H2 S O5 > H2 S O3 > S Cl2 > H2 S S O3 > S O2 > S8 > H2 S H2 S O4 > S O2 > H2 S > H2 S2 O8
Asked by asurve | 10 Sep, 2019, 11:57: PM
answered-by-expert Expert Answer
Incorrect order of decreasing oxidation number of S in the compound is in 4th option.
 
Oxidation space number space of space straight S space in space straight H subscript 2 SO subscript 4 minus left parenthesis plus 1 right parenthesis cross times 2 plus straight x plus left parenthesis negative 2 right parenthesis cross times 4 equals 0 2 plus straight x minus 8 equals 0 straight x minus 6 equals 0 straight x equals 6 In space SO subscript 2 minus straight x minus left parenthesis negative 2 right parenthesis cross times 2 equals 0 straight x minus 4 equals 0 straight x equals 4 In space straight H subscript 2 straight S minus open parentheses plus 1 close parentheses cross times 2 plus straight x equals 0 straight x equals negative 2 In space straight H subscript 2 straight S subscript 2 straight O subscript 8 minus plus 1 cross times 2 plus 2 straight x plus left parenthesis negative 2 right parenthesis cross times 8 equals 0 2 straight x minus 14 equals 0 straight x equals plus 7 B u t space i t space i s space n o t space p o s s i b l e space b e c u s e space o x i d a t i o n space s t a t e space o f space S space i s space f r o m space minus 2 space t o space plus 6. I n space space straight H subscript 2 straight S subscript 2 straight O subscript 8 space peroxide space linkage space is space present space. space in space it apostrophe straight s space structure comma space straight A space sulphur space atom space makes space t w o space double space bond space with space oxygen comma space one space single space bond space with space oxygen space atom. space One space single space bond space with space OH space group. So space it apostrophe straight s space oxidation space state space will space be space space space minus 1 plus left parenthesis negative 1 right parenthesis plus left parenthesis negative 2 right parenthesis 2 plus x equals 0 space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space x equals 6
Answered by Ravi | 11 Sep, 2019, 12:13: PM

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The incorrect order of decreasing oxidation number of S in compounds is: H2 S2 O7 > Na2 S4 O6 > Na2 S2 O3 > S8 H2 S O5 > H2 S O3 > S Cl2 > H2 S S O3 > S O2 > S8 > H2 S H2 S O4 > S O2 > H2 S > H2 S2 O8
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