the horizontal distance travelled by a bullet fired at 45 degree is 360 m. if it is fired from a lorry moving in the direction of bullet with a uniform velocity 18 KM/HR and with the same elevation, what is the horizontal distance travelled by the bullet
Asked by vedant sharma | 21st Sep, 2014, 11:50: AM
Given that when θ = 45°, horizontal range, R=360 m.
Let u be the velocity with which the bullet is fired and v be the velocity of the lorry.
Given that the lorry is moving with a uniform velocity, v= 18 km/ hr =(18×5/18)m/s = 5 m/s
In horizontal direction, as the motion is uniform the acceleration is zero.
So we can write the displacement in the horizontal direction as R = ux × T
Here ux = u cos θ+ v
uy = u sin θ
Hence Horizontal range R = (u cosθ+v)× T ---------(1)
The horizontal distance travelled by the bullet = 402.9 m
Answered by Jyothi Nair | 23rd Sep, 2014, 12:55: PM
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