the freezing pointof a 0.05 molal solution of a non electrolyte in water is
 

Asked by sarvaterahul | 1st Jul, 2016, 08:25: AM

Expert Answer:

∆Tf = kf x m = 1.86 x 0.05 = 0.093°C

Freezing point = 0-0.093 = -0.093°C

Answered by Vaibhav Chavan | 1st Jul, 2016, 09:18: AM