The Fourth term of an A.P. is ten times the first. Prove that the sixth term is four times the second term.
Asked by sarika vijay kumar | 6th Sep, 2011, 05:34: PM
The formula for nth term of an A.p is a+(n-1)d,where a is the first term,d is the common difference.
Given,4th term=10 a.
Thus,sixth term=4(4a)=4(2nd term)
Answered by | 6th Sep, 2011, 06:32: PM
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