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CBSE Class 8 Answered

The force on a cylindrical box is 1.2N . It has a circular cross section of radius 10cm . What pressure does it exert on the surface on which it is kept in a standing position?
Asked by Shawn | 11 Sep, 2015, 11:24: AM
answered-by-expert Expert Answer
The force on the box is F = 1.2 N
 
The radius of circular cross-section is r = 10 cm = 0.1 m
 
Now, pressure exerted by the cylinder in standing position on the surface is
 
begin mathsize 14px style straight P equals straight F over straight A equals straight F over πr squared equals fraction numerator 1.2 over denominator 3.14 cross times 0.1 squared end fraction equals 38.2 space straight N divided by straight m squared equals 38.2 space Pa end style
Answered by Romal Bhansali | 11 Sep, 2015, 12:02: PM

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