The force between charges placed in vacuum is F.

Asked by sweety | 11th Jun, 2013, 11:28: PM

Expert Answer:

When 2 charges are placed in the vacuum then, F = 1/4pie0 * q1q2/r^2
 
Now, when the same 2 charges are dipped in the kerosene oil, then the electric force between them would be F1 = 1/4pie0K * q1q2/r^2,
now K = 2 and F = 1/4pie0 * q1q2/r^2
Hence, F1 = F/2

Answered by  | 12th Jun, 2013, 01:54: AM

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