the first line of balmer series of He ion has a wavelength of 164 nm. the wavelength of the series limit is?
Asked by
| 11th Jun, 2011,
05:20: PM
Expert Answer:
Ans. (d)
According to Rydberg equation,
For first line in Balmer series, n1 =2 n2=3
zTherefore 1/ 164 = RH{1/22-1/32}
For the series limit
Dividing equation (1) by (2)
?/164 =5 X4 /36
=91.2
The wavelength of the series limit is 91.2
Ans. (d)
According to Rydberg equation,
For first line in Balmer series, n1 =2 n2=3
zTherefore 1/ 164 = RH{1/22-1/32}
For the series limit
Dividing equation (1) by (2)
?/164 =5 X4 /36
=91.2
The wavelength of the series limit is 91.2
Answered by
| 13th Jun, 2011,
05:20: PM
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