.The Fig., shows two concentric circles with centre O. AB and APQ are tangents to the inner circle from point A lying on the outer circle. If AB=7.5 cm then find AQ

Asked by  | 28th Feb, 2013, 04:05: PM

Expert Answer:

Join OP. Now since, APQ is a tangent to the smaller circle so, OP = 90 degree. 
 
Since, the length of tangents drawn from a common point to a circle is equal
So, AB = AP
 
Also, in the bigger circle, AQ is the chord and OP is the perpendicular to the chord. 

Since, in a circle, a perpendicular drawn from the center of the circle to a chord bisects it. 
Therefore, AP = PQ. 
 
Hence, AQ = AP+PQ = 2*AP = 2* AB = 2*(7.5) = 15 cm

Answered by  | 28th Feb, 2013, 04:32: PM

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