The equation z^2+az+b=0 has a purely imaginary root where a&b are complex constants.Prove that a+conjugate of a)(a*conjugate of b+conjugate of a*b)+(b-conjugate of b)^2=0

Asked by nilay pandey | 10th Oct, 2013, 11:51: PM

Expert Answer:

Answered by Dhrubajit | 12th Oct, 2013, 11:13: AM

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