The equation of a line is given by (4-x)/2=(y+3)/3=(z+2)/6 . Write the direction cosines of a line parallel to the above line. The answer given in the book is:(-2)/7 ,3/7 ,6/7

Asked by Manoj | 1st Jun, 2013, 05:35: PM

Expert Answer:

(4-x)/2=(y+3)/3=(z+2)/6
(x-4)/-2=(y+3)/3=(z+2)/6
direction ratios (l,m,n) = (-2,3,6)
Direction cosines = [l/sqrt(l^2+m^2+n^2) , m/sqrt(l^2+m^2+n^2), n/sqrt(l^2+m^2+n^2)]
Direction cosines = [-2/7, 3/7, 6/7]

Answered by  | 2nd Jun, 2013, 05:26: AM

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