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CBSE Class 9 Answered

the engine of a train has to apply a force 5000n to over come friction to run at uniform rate of of 90 km per h .what is the power?
Asked by yash | 29 Nov, 2013, 07:19: AM
answered-by-expert Expert Answer
The speed of train = 90 km/h = 90 × 5/18 = 25 m/s
 
Thus, in one second, the train will travel a distance of 25 m.
 
Hence, work done by the engine is
 
W = Fs = 5000 × 25 = 125000 J
 
Thus, the power generated by the engine is
 
P = W/t = 125000/1 = 125000 W
Answered by Romal Bhansali | 29 Nov, 2013, 10:12: AM

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