the emf e=4cos1000t is applied to an L-R circuit containing inductance 3mH &resistance 4ohm.the amplitude of current is

 

Asked by smithasaji12 | 5th Jun, 2020, 08:50: PM

Expert Answer:

i space equals fraction numerator V o l t a g e space left parenthesis V right parenthesis over denominator I m p e d a n c e space left parenthesis Z right parenthesis end fraction
Z squared space equals space R squared plus X subscript L squared space equals space square root of space R squared plus X subscript L squared end root space equals space square root of space R squared plus open parentheses omega L close parentheses squared end root space equals space square root of space R squared plus open parentheses 2 pi f L close parentheses squared end root
t h u s comma space
i space equals space fraction numerator 4 over denominator square root of 4 squared plus open parentheses 2 pi cross times begin display style fraction numerator 1000 over denominator 2 pi end fraction end style cross times 3 cross times 10 to the power of negative 3 end exponent close parentheses squared end root end fraction space equals space fraction numerator 4 over denominator square root of 25 end fraction equals 4 over 5 equals 0.8 space A space

Answered by Shiwani Sawant | 5th Jun, 2020, 10:21: PM

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