The distance traveled by a body in the nth second is given by the expression (2+3n).Find the initial velocity & acceleration. Also, find the final velocity at the end of 2 seconds.

Asked by Shourya Mukherjee | 10th May, 2012, 10:02: PM

Expert Answer:

Distance travelled by an object in n th sec=u+a(2n-1)/2   this is formula
so,    2+3n=u+a(2n-1)/2
        2+3n=u+an-a/2
 
now equating both parts:
an=3n         2=u-a/2
a=3             u=7/2=3.5m/s

Answered by  | 14th May, 2012, 03:40: PM

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