The distance-time graph for a car is given. 



Assume that the car moves with uniform speed, answer the following:

(a) During which period was the car traveling at the greatest speed?

(b) During which period was the car moving with the least speed?

(c) What is the average speed of the car between 10.15 am and 11.15 am?

(d) What is the average speed of the car for the entire journey?

Asked by Topperlearning User | 15th Jun, 2016, 11:09: AM

Expert Answer:

The slope of distance time graph is represents the speed of the object.

(a)The greatest inclination (slope) with the time-axis occurs in the part DE of the graph. Thus, the speed is greatest between 11.25am and 11.35am.

(b)The least inclination with the time-axis occurs in the part CD. Thus, the speed is least between 11.05 am and 11.15 am.

(c)The distance travelled between 10.15 am and 11.15 am is 30 km, and the time interval is 1 hour.
Thus, the average speed is = 30 km / 1 h = 30 km/h

(d)The total distance travelled is 50 km and the total time taken is 1 hour 30min = (3/2) h
Thus, the average speed is 

Answered by  | 15th Jun, 2016, 01:09: PM