CBSE Class 10 Answered
The difference of squares of two natural
numbers is 45. The square of the smaller number is four times the larger
number. Find the numbers.
Asked by Topperlearning User | 04 Jun, 2014, 01:23: PM
Expert Answer
Let the two numbers be x and y such that y < x.
From the given conditions, we have:
x2 - y2 = 45 … (1)
y2 = 4x … (2)
Using (2) in (1), we have:
x2 - 4x - 45 = 0
(x - 9)(x + 5) = 0
x = 9 (Rejecting the negative value of x)
From (2), we get, y = 6 or -6
Rejecting the negative value, we have, y = 6.
Thus, the two numbers are 9 and 6.
Answered by | 04 Jun, 2014, 03:23: PM
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