The Dielectric strength of air is 3*10V /m. A parallel plate capacitor has area 20cm2 and plate separation of 0.1mm. Find the maximum rms voltage of an A/C source which can be safely connected to this capacitor.

Asked by Malavika Umesh | 29th Sep, 2014, 08:49: PM

Expert Answer:

begin mathsize 14px style Given : Dielectric space strength space of space air space straight V equals 3 cross times 10 to the power of 6 space straight V divided by straight m Area space straight A equals 20 space cm squared Plate space separation space straight d equals 0.1 space mm straight E equals straight V over straight d straight V equals straight E. straight d equals 3 cross times 10 to the power of 6 cross times 10 to the power of minus 4 end exponent equals 300 space straight V straight V subscript rms equals fraction numerator straight V subscript straight p over denominator square root of 2 end fraction equals fraction numerator 300 over denominator square root of 2 end fraction equals 300 cross times 0.707 equals 210 space straight V Hence comma space maximum space rms space voltage space of space an space AC space source space which space can space be space connected space is space 210 space straight V end style

Answered by Priyanka Kumbhar | 30th Sep, 2014, 11:42: AM