the diagonals of aquadrilateral abcd bisect each other at the point osuch that ao/bo=co/do. show th

Asked by  | 13th Aug, 2009, 09:09: PM

Expert Answer:

consider triangles AOB,COD



angle AOB=angle DOC..Vertically opp angles


 triangle AOB similar to triangle COD....SAS rule

angle OAB= angle OCD....corr anglesof similar triangles


AD parallel to BC... since alt angles are equal.

ABCD is a trapezium as one pair of opp sides is parallel



Answered by  | 14th Aug, 2009, 08:00: AM

Queries asked on Sunday & after 7pm from Monday to Saturday will be answered after 12pm the next working day.