the diagonal of a square A is (a+b) . Find the diagonal of square B whose area is twice the area of A.
Asked by | 26th Aug, 2012, 07:11: PM
Let x be the side of square a.
Diagonal = (root 2)x
Therefore, a + b = (root 2)x
This gives x = (a + b) / (root 2)
Hence, Area of square A = x2 = (a + b)2 / 2
Given, Area of square B = 2 Area of square A
So, Area of square B = (a + b)2
Hence, side of square B = a + b
Now, you can easily find the diagonal of the square B.
Answered by | 26th Aug, 2012, 07:44: PM
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