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 THE DENSITY OF ICE IS 917KG/M3 AND THE APPROXIMATELY DENSITY OF THE SEA WATER IN WHICH AN ICEBERG FLOATS IS 1025KG/M3.WHAT FRACTION OF THE ICEBERG IS BENEATH ? 

Asked by M.s.srinidhi21 | 19 Oct, 2014, 04:41: PM
answered-by-expert Expert Answer
By the principle of floatation,
 
begin mathsize 14px style fraction numerator Volume space of space iceberg space immersed over denominator Total space volume space of space iceberg end fraction equals fraction numerator Density space of space ice over denominator Density space of space sea space water end fraction Given space density space of space ice space equals space 917 space kg space divided by straight m cubed comma space Density space of space sea space water space equals space 1025 space kg space divided by straight m cubed fraction numerator Volume space of space iceberg space immersed over denominator Total space volume space of space iceberg end fraction equals fraction numerator 917 space kg space divided by straight m cubed over denominator 1025 space kg space divided by straight m cubed end fraction space space space equals 0.89 Thus space 0.89 to the power of th space part space of space volume space of space iceberg space will space remain space beneath space the space water space surface. space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space end style
Answered by Jyothi Nair | 20 Oct, 2014, 08:49: AM

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