The density of 15% Sulphuric Acid solution is 1.1g/cm3. What Volume of 95% sulphuric acid density = 1.85g/cm3 and what mass of water must be taken to prepare 1 litre 15% of sulphuric acid solution?

Molecular mass of sulphuric acid= 1 X2 +32 +16 X4 = 98

Molarity= Density X strength X10/molar mass

Molarity of first solution = 1.1 X 15 X10/98

Molarity ₁= 1.68 M

Molarity of second solution = 1.85 X 95 X10/98 

Molarity ₂= 17.93 M

 

using

 

M₁ X V ₁ = M ₂ X V ₂

 

_{17.93 X V = 1.68 X 1000}

 

_{V= 93.7cm ³} 

 

 

Now mass of 1000 cm ³  of 15 %   sulphuric acid= 1000X 1.10 = 1100 gm

Mass of 93.7  cm ³of 95 % sulphuric acid = 93.7 X 1.85 = 173.34

So mass of water =  1100 - 173.4= 926.6 gm