The de broglie wavelength of a particle with mass 1kg and velocity 100m/s is 

Asked by arushidabhade | 8th Jul, 2019, 08:05: PM

Expert Answer:

Given:
 
mass, m = 1 kg
 
velocity, v = 100 m/s
 
h = 6.63×10-27 erg.sec
 
De broglie wavelength is given by,
 
straight lambda space equals space straight h over mv

space space space equals space fraction numerator 6.63 cross times 10 to the power of negative 34 end exponent over denominator 1 cross times 100 end fraction

straight lambda space equals 6.63 cross times 10 to the power of negative 36 space end exponent straight m
 
De Brogli's wavelength is 6.63×10-36 m

Answered by Varsha | 9th Jul, 2019, 02:52: PM