the composition of a sample of iron ore is Fe.93 O 1.00.What percentage of iron is in the form of Fe(III)
Asked by dipak kumar Saikia | 12th Jul, 2013, 02:34: AM
Suppose the number of atoms of Fe 3+ ions present is = x.
Then tn=he number of atoms of Fe2+ ions would be = (o.93 - x )
So, the total number of O2- ions = 1
For an electrically neutral compound,
total positive charge from Fe2+ + Fe 3+ = total negative charge from O2- ions.
Thus 3x + (0.93 - x ) x2 = 2
or, x + 1.86 = 2.
x = ( 2 - 1.86) = 0.14
% of Fe 3+ ions 0.14
------ x 100 = 15.05
% of Fe 3+ ions is 15.05 %.
Answered by | 17th Jul, 2013, 10:42: PM
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