the composition of a sample of iron ore is Fe.93 O 1.00.What percentage of iron is in the form of Fe(III)

Asked by dipak kumar Saikia | 12th Jul, 2013, 02:34: AM

Expert Answer:

Suppose the number of atoms of Fe 3+ ions present is = x.
Then tn=he number of atoms of Fe2+ ions would be = (o.93 - x )
So, the total number of O2- ions = 1
 
For an electrically neutral compound,
total positive charge from  Fe2+ + Fe 3+ = total negative charge from   O2- ions.
 
Thus 3x  + (0.93 - x ) x2  = 2
or, x  + 1.86   = 2.
x = ( 2 - 1.86) = 0.14
% of Fe  3+ ions    0.14  
                       ------   x 100  = 15.05 
                        0.93
 
 
% of Fe  3+ ions is 15.05 %.
 

Answered by  | 17th Jul, 2013, 10:42: PM

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