the ceiling of a long hall is 25 m high.what is the maximum horizontal distance that a ball thrown

Asked by  | 26th Jul, 2009, 12:50: AM

Expert Answer:

Since the ceiling of hall is 25 m high therefore the max. height attained by the ball will be 25m.

i.e. H = 25m, u = 40 m/s  [given]

we know, H  =  u2sin2θ / 2g

or, sin2θ = 2gH / u2   = 2 x 9.8 x 25 / ( 40 )2  = 0.30625

or, sin  θ = 0.5534

or, θ = 33.6 o

Therefore, R = u2sinθ / g  =  (40)2  sin 67.2o /9.8

                                              =  150.5 m

Answered by  | 26th Jul, 2009, 12:10: PM

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